A로 B 만들기

문제 설명
문자열 before와 after가 매개변수로 주어질 때, before의 순서를 바꾸어 after를 만들 수 있으면 1을, 만들 수 없으면 0을 return 하도록 solution 함수를 완성해보세요.

제한사항
0 < before의 길이 == after의 길이 < 1,000
before와 after는 모두 소문자로 이루어져 있습니다.

입출력 예
before after result
"olleh" "hello" 1
"allpe" "apple" 0

---

import java.util.Arrays;

class Solution {
    public int solution(String before, String after) {
        int answer = 0;
        char[] beforeChars = before.toCharArray();
        char[] afterChars = after.toCharArray();
        
        Arrays.sort(beforeChars);
        Arrays.sort(afterChars);
        
        if(Arrays.equals(beforeChars, afterChars)) {
            answer = 1;
        } else {
            answer = 0;
        }
        
        return answer;
    }
}

---

...